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00:00 - 00:59 | the question is that using vector method prove that the line segment joining the midpoints of the adjacent sides of a quadrilateral taken in order form a parallelogram we need to draw a diagram for this so this is our diagram and from this let ABCD is a quadrilateral and as per the diagram pqrs are midpoints of Ab BC CD and the sides from this week and right position vectors of pqrs are for Peeth will be vector A + vector B by 2 call Kyon it will be web |

01:00 - 01:59 | b + vector C by 24 hour it will be vector C plus vector De by 2 and for as it will be vector A + vector by 2 respectively now from the diagram we can see that PQ vector is equal to position vector of cube minus position vector of so that will be equal to vector b + vector C by 2 minus vector A + vector B by 2 which is equal to vector B by 2 + vector C by 2 minus vector a by 2 minus vector B by 2 by 2 and |

02:00 - 02:59 | Dubai to will be cancelled and this leaves vector C - vector a bi similarly SR vector will be equal to position vector of our - position vector of S and that will be equal to C vector + b vector by 2 minus b vector + b vector by to this will give us get - vector a to therefore it is clearly visible that PQ vector is equal to SR vector which implies PQ is parallel to SR and PQ is equal to SR similarly for the other two |

03:00 - 03:59 | we can prove that p s is equal to Q R and p s is parallel to QR so this implies that since PS is parallel to QR and PQ is parallel to SR and PS is equal to Q R and PQ is equal to SR this implies pqrs is a parallelogram I hope you got addicted thank you |