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Asked Dec 12, 2019
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Speedy car care monitors its operations carefully. This week 16 oil change jobs were sampled with a sample mean of 18 minutes per job and a sample standard deviation of 9 minutes. Based on this week's sample the lower limit of a 95% confidence interval for the mean is?

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Expert Answer

Step 1

It is given that the sample mean and standard deviation are 18 and 9, respectively. The sample size (n) is 16.

Step 2

The 95% confidence interval for the mean is obtained as follows:

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95% CI =x±t = 18±toos J16. /Using Excel formula "T.INV.2T(0.05,15)" = 18+2.131(2.25) (13.205, 22.795)

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