Spitting cobras can defend themselves by squeezing muscles around their venom glands to squirt venom at an attacker. Suppose a spitting cobra rears up to a height of 0.440 m above the ground and launches venom at 3.40 m/s, directed 41.0° above the horizon. Neglecting air resistance, find the horizontal distance (in m) traveled by the venom before it hits the ground.

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Asked Oct 14, 2019
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Spitting cobras can defend themselves by squeezing muscles around their venom glands to squirt venom at an attacker. Suppose a spitting cobra rears up to a height of 0.440 m above the ground and launches venom at 3.40 m/s, directed 41.0° above the horizon. Neglecting air resistance, find the horizontal distance (in m) traveled by the venom before it hits the ground.
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Given Launched angle, O= 41.0 Lacenched velocty, v 340 ml (apwera) k

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venom islaunched at point O and hits the g>orund at point P. InHal vertfcal velocity, V= V Sinft1.0) IniHal Horjontal velociy, V= V Cos (4l.6) Diveckon of gai in vertcally dlownward g= -9. t mls) Net verhcal displacement fom He point o, is (s=-0.440 m) In the hoigontal disechon, aco berehon (a-o)

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Using thfrd kinematic eguaton of motiom fn the vestical olfsechon S=t-at 0-44m(3.40m/sSin 41.0)t-(9-8l /s)t fearangin the abore eguation 4.9 mle)2.23 myt - 0.4m = o

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