Spitting cobras can defend themselves by squeezing muscles around their venom glands to squirt venom at an attacker. Suppose a spitting cobra rears up to a height of 0.520 m above the ground and launches venom at 3.10 m/s, directed 43.0° above the horizon. Neglecting air resistance, find the horizontal distance (in m) traveled by the venom before it hits the ground.

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Asked Oct 12, 2019
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Spitting cobras can defend themselves by squeezing muscles around their venom glands to squirt venom at an attacker. Suppose a spitting cobra rears up to a height of 0.520 m above the ground and launches venom at 3.10 m/s, directed 43.0° above the horizon. Neglecting air resistance, find the horizontal distance (in m) traveled by the venom before it hits the ground.

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Expert Answer

Step 1

Consider the kinematic diagram of venom.

3JOn
10-430
1 1
0.52m
uos43
ground
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3JOn 10-430 1 1 0.52m uos43 ground

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Step 2

Write the expression of range for the projectile motion from the point P and solve it for range AB.

u sin 20
R
(3.1 m/s) sin 2(43)
9.81 m/s
=0.977 m
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u sin 20 R (3.1 m/s) sin 2(43) 9.81 m/s =0.977 m

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Step 3

Write the equation of motion for the venom at point Q an...

1
SBu,cgtac
Consider downward direction as positive. Thus,
1
(0.52 m) (3.10 m/s (sin 43°))3c +(9.81 m/s
')thc
tBc 0.174 s
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1 SBu,cgtac Consider downward direction as positive. Thus, 1 (0.52 m) (3.10 m/s (sin 43°))3c +(9.81 m/s ')thc tBc 0.174 s

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