Question
Asked Oct 12, 2019
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Spitting cobras can defend themselves by squeezing muscles around their venom glands to squirt venom at an attacker. Suppose a spitting cobra rears up to a height of 0.520 m above the ground and launches venom at 2.50 m/s, directed 37.0° above the horizon. Neglecting air resistance, find the horizontal distance (in m) traveled by the venom before it hits the ground.

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Expert Answer

Step 1

Using equation of motion,

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-0.520m-(2.50m/s)(sin 37°) -; (9,8m/s') | 4.9r2-1.505t-0.520 = 0

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Step 2

Solving using quadratic formula,

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-(-1.505)-1.505)-(4)(4.9)(-0.520) 2(4.9) (Ignoring thenegative value) 0.514s

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Step 3

Horizontal dist...

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x( cos e) =(2.50m/s)(cos 37°)(0.514 s) =1.03m

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Science

Physics

Kinematics

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