Step 1: Determine the total positive charge on the hexapeptide when all acidic and basic groups are fully protonated. Enter your answer without the sign. charge: Step 2: Determine the pK value of the group that loses a proton to form the zwitterionic species with a net charge pK = of zero. Step 3: Determine the pK value of the group that gains a proton to form the zwitterionic species with a net charge pK = of zero. Step 4: Estimate the pl value of the hexapeptide. pI =

Organic Chemistry
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ISBN:9781305080485
Author:John E. McMurry
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Chapter26: Biomolecules: Amino Acids, Peptides, And Proteins
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Step 1: Determine the total positive charge on the
hexapeptide when all acidic and basic groups are fully
charge:
protonated. Enter your answer without the sign.
Step 2: Determine the pK value of the group that loses a
proton to form the zwitterionic species with a net charge
pK =
of zero.
Step 3: Determine the pK value of the group that gains a
proton to form the zwitterionic species with a net charge
pK =
of zero.
Step 4: Estimate the pI value of the hexapeptide.
pl =
Transcribed Image Text:Step 1: Determine the total positive charge on the hexapeptide when all acidic and basic groups are fully charge: protonated. Enter your answer without the sign. Step 2: Determine the pK value of the group that loses a proton to form the zwitterionic species with a net charge pK = of zero. Step 3: Determine the pK value of the group that gains a proton to form the zwitterionic species with a net charge pK = of zero. Step 4: Estimate the pI value of the hexapeptide. pl =
Isoelectric focusing can separate peptides based on their relative contents of
acidic and basic residues. When voltage is applied to an electrophoretic gel with
Amino acid
pK
Arg
12.5
a pH gradient, each peptide migrates until it reaches a point where it has no net
charge. The pH at this point is the isoelectric point (pl) for that peptide.
Asp
3.7
Cys
8.2
One can estimate the pl fairly accurately (within 0.1 or 0.2 pH units) using the
Glu
4.3
pK values of all the proton dissociable groups in the peptide.
His
6.0
Consider the hexapeptide Met-Asp-Lys-Arg-Ala-Tyr.
Lys
10.5
Tyr
10.5
*peptide-NH;
8.0
*peptide-COOH
3.4
* Amino and carboxy terminal values differ
from the a amino and carboxy values of a
single amino acid.
Step 1: Determine the total positive charge on the
hexapeptide when all acidic and basic groups are fully
charge:
protonated. Enter your answer without the sign.
Transcribed Image Text:Isoelectric focusing can separate peptides based on their relative contents of acidic and basic residues. When voltage is applied to an electrophoretic gel with Amino acid pK Arg 12.5 a pH gradient, each peptide migrates until it reaches a point where it has no net charge. The pH at this point is the isoelectric point (pl) for that peptide. Asp 3.7 Cys 8.2 One can estimate the pl fairly accurately (within 0.1 or 0.2 pH units) using the Glu 4.3 pK values of all the proton dissociable groups in the peptide. His 6.0 Consider the hexapeptide Met-Asp-Lys-Arg-Ala-Tyr. Lys 10.5 Tyr 10.5 *peptide-NH; 8.0 *peptide-COOH 3.4 * Amino and carboxy terminal values differ from the a amino and carboxy values of a single amino acid. Step 1: Determine the total positive charge on the hexapeptide when all acidic and basic groups are fully charge: protonated. Enter your answer without the sign.
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