# Suppose 234.3 mg of PbCl2  was added to 16.0 mL of water in a flask, and the solution was allowed to reach equilibrium at 21.0 oC.  Some solute remained at the bottom of the flask after equilibrium, and the solution was filtered to collect the remaining PbCl2, which had a mass of 91.6 mg .  What is the solubility of PbCl2 (in g/L)?-Express the concentration in grams per liter to three significant figures.

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Suppose 234.3 mg of PbCl2  was added to 16.0 mL of water in a flask, and the solution was allowed to reach equilibrium at 21.0 oC.  Some solute remained at the bottom of the flask after equilibrium, and the solution was filtered to collect the remaining PbCl2, which had a mass of 91.6 mg .  What is the solubility of PbCl2 (in g/L)?
-Express the concentration in grams per liter to three significant figures.
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Step 1

Solubility: solubility is a chemical property referring to the ability for a given substance, the solute, to dissolve in a solvent.

Step 2

Given:

Mass of PbCl2 taken = 234.3 mg

Mass of PbCl2 left in flask = 91.6 mg.

Volume of water = 16.0 mL.

Amount of PbCl2 dissolved = Mass of PbCl2 taken - Mass of PbCl2 left in flask

Amount of PbCl2 dissolved = 234.3 mg – 91.6 mg = 142.7 mg.

Step 3

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