Suppose 3.20 g of copper are reacted with excess nitric acid according to the given equation, and 6.32 g Cu(NO3)2 product are obtained.   Cu(s)+4HNO3(aq)⟶Cu(NO3)2(aq)+2NO2(g)+2H2O(l)   What is the theoretical yield of Cu(NO3)2? What is the percent yield of Cu(NO3)2?

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Chapter5: Stoichiometry
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Suppose 3.20 g of copper are reacted with excess nitric acid according to the given equation, and 6.32 g Cu(NO3)2 product are obtained.

 

Cu(s)+4HNO3(aq)⟶Cu(NO3)2(aq)+2NO2(g)+2H2O(l)

 

What is the theoretical yield of Cu(NO3)2?

What is the percent yield of Cu(NO3)2?

 

Suppose 3.20 g of copper are reacted with excess nitric acid according to the given equation, and 6.32 g Cu(NO3)2 product
are obtained.
Cu (s) + 4 HNO3 (aq) → Cu(N03)2 (aq) + 2 NO2 (g) + 2 H2O (1)
What is the theoretical yield of Cu(NO3)2 ?
g
What is the percent yield of Cu(NO3)2 ?
Transcribed Image Text:Suppose 3.20 g of copper are reacted with excess nitric acid according to the given equation, and 6.32 g Cu(NO3)2 product are obtained. Cu (s) + 4 HNO3 (aq) → Cu(N03)2 (aq) + 2 NO2 (g) + 2 H2O (1) What is the theoretical yield of Cu(NO3)2 ? g What is the percent yield of Cu(NO3)2 ?
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