Suppose a company produces lightbulbs with a mean lifetime of 1000 hours and a standard devlation of 50 hours. So, the z-score for a particular Ilghtbulb that lasts for only 700 hours Is O A. 300 О В. -6 ОС. 50 O D. 6
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- The shape of the mean-variance frontier that results from the combination of a riskless and arisky asset is…..:a. Is U-shaped, tilted 90 degrees clockwise.b. Is a straight line passing from the mean-variance points of the two assets.c. Is a hyperbola.d. Consists of two straight lines, each connecting one of the two assets to a risk-freeportfolioSuppose a distribution mean=20,median=10 and SD=15 find co efficient of skewnessThe data in the attached image represents blood pressure based on a new trial medication used in an experiment involving a total of 50 male and female subjects. There were two levels of treatment: 0 = placebo and 1 = treatment group. Family History Blood Pressure = Fam-Hist-BP; from the paternal side = PS; from the maternal side = MS; from both sides = BS; none on both sides or not known = N.; Blood pressure before the experiment = BP-Before-Exp; Blood pressure after the experiment = BP-After-Exp. Task: Construct a side-by-side boxplot to compare the variables BP-Before-Exp and BP-After-Exp.
- The data in the attached image represents blood pressure based on a new trial medication used in an experiment involving a total of 50 male and female subjects. There were two levels of treatment: 0 = placebo and 1 = treatment group. Family History Blood Pressure = Fam-Hist-BP; from the paternal side = PS; from the maternal side = MS; from both sides = BS; none on both sides or not known = N.; Blood pressure before the experiment = BP-Before-Exp; Blood pressure after the experiment = BP-After-Exp. Task: Construct a scatterplot to display the relationship and find the correlation between age and BP-Before Exp.The data in the attached image represents blood pressure based on a new trial medication used in an experiment involving a total of 50 male and female subjects. There were two levels of treatment: 0 = placebo and 1 = treatment group. Family History Blood Pressure = Fam-Hist-BP; from the paternal side = PS; from the maternal side = MS; from both sides = BS; none on both sides or not known = N.; Blood pressure before the experiment = BP-Before-Exp; Blood pressure after the experiment = BP-After-Exp. Task: Construct a histogram to represent the family BP history, the subjects' BP before treatment and the subjects' BP after treatment.The data in the attached image represents blood pressure based on a new trial medication used in an experiment involving a total of 50 male and female subjects. There were two levels of treatment: 0 = placebo and 1 = treatment group. Family History Blood Pressure = Fam-Hist-BP; from the paternal side = PS; from the maternal side = MS; from both sides = BS; none on both sides or not known = N.; Blood pressure before the experiment = BP-Before-Exp; Blood pressure after the experiment = BP-After-Exp. Task: Construct a scatterplot to display the relationship and find the correlation between BP-Before-Exp and BP-After-Exp.
- A simple random sample of heights of 6400Englishmen has a mean of 67.85 inches and SD 2.56 inches, while a simple random sample of heights of 1600 Australians has a mean of 68.55 inches and SD of 2.52 inches. D the data indicate that Australians are, on the average, taller than Englishmen?Toward the middle of the harvesting season, peaches for canning come in three types, early, late, and extra late, depending on the expected date of ripening. During a certain week, the data to the right were recorded at a fruit delivery station. Complete parts (a) through (d) below. 40 trucks went out carrying early peaches; 76 carried late peaches; 64 carried extra late peaches; 31 carried early and late; 34 carried late and extra late; 13 carried early and extra late; 6 carried all three; 8 carried only figs (no peaches at all). a. How many trucks carried only late variety peaches? b. How many carried only extra late? c. How many carried only one type of peach? d. How many trucks (in all) went out during the week? Thank you so muchA UPS efficiency expert is interested in finding out if the years of driving experience (EXP) can be used to predict the frequency of late deliveries (LATE). Here are the data (late deliveries are per 100 ): EXP ZEXP LATE ZLATE 16 0.49 8 0.43 19 1.34 10 1.45 15 0.21 7 -0.09 15 0.21 8 0.43 14 -0.07 6 -0.60 15 0.21 8 0.43 13 -0.35 5 -1.11 12 -0.64 5 -1.11 4 -2.90 3 -2.14 15 0.21 8 0.43 16 0.49 9 0.94 17 0.78 9 0.94 MEXP = 14.25 SDEXP = 3.54 MLATE= 7.17 SDLATE = 1.95 Use α = .05 for all decisions. Determine how many late deliveries (per 100) we would predict for a driver with 20 years of experience. No explanation is required – just report the predicted value as your final answer.
- Toward the middle of the harvesting season, peaches for canning come in three types, early, late, and extra late, depending on the expected date of ripening. During a certain week, the data to the right were recorded at a fruit delivery station. Complete parts (a) through (d) below. 40 trucks went out carrying early peaches; 71 carried late peaches; 52 carried extra late peaches; 26 carried early and late; 32 carried late and extra late; 11 carried early and extra late; 6 carried all three; 5 carried only figs (no peaches at all). a) How many trucks carried only late variety peaches? trucks (Type a whole number.) (b) How many carried only extra late? trucks (Type a whole number.) (c) How many carried only one type of peach? trucks (Type a whole number.) (d)How many trucks (in all) went out during the week? trucks (Type a whole number.)The owner of Showtime Movie Theaters, Inc., would like to predict weekly gross revenue as a function of advertising expenditures. Historical data for a sample of eight weeks follow. Weekly Gross Revenue ($1000s) Televison Advertising ($1000s) Newspaper Advertising ($1000s) 97 6 1.5 90 2 2 95 5 1.5 93 3.5 2.5 95 3 4.3 95 3.5 3.3 95 3.5 4.2 95 4 2.5 a. Use alpha= 0.01 to test the hypotheses Ho : Beta Sub1= Beta Sub2 =0 Ha : Beta Sub1 and/or Beta Sub2 is not equal to zero for the model y=Beta Sub 0+ Beta Sub1 Xsub1+Beta Sub2 Xsub2+E , where X1= television advertising ($1000s) X2+ newspaper advertising ($1000s) Compute the F test statistic (to 2 decimals). Use F table. What is the p-value? - Select your answer -less than .01between .01 and .025between .025 and .05between .05 and .10greater than .10Item 2 What is your conclusion? - Select your answer -The overall model is not significantThe overall model is significantItem 3 b. Use alpha =0.05 to…From past records a firm has noted that the average time its employees take for tea break is 15 minutes , with variance 4 minutes. A new employee joins the firm and over 50 tea breaks he has been observed to take an average time of 17 minutes. Should the manager caution him about taking too long a time over his tea break ?
