Suppose a golf ball is driven so that it travels a distance of 200 feet as measured along the ground and reaches an altitude of 500 feet. If the origin represents the tee and is the ball travels along aparabolic path over the positive x-axis, find an equation for the path of the golf ball.Which form does the equation fit?(y – k)2 = 4 c(x – h)(x – h)² = 4c(y – k)(x – h)? + y – k)²q?p2(х — Һ)? —(y – k)?p2q?(x – h)? _ y – k)²p2q?Withh = 100k= 500p? := DNEq? = DNE

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Asked Dec 4, 2019
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Suppose a golf ball is driven so that it travels a distance of 200 feet as measured along the ground and reaches an altitude of 500 feet. If the origin represents the tee and is the ball travels along a
parabolic path over the positive x-axis, find an equation for the path of the golf ball.
Which form does the equation fit?
(y – k)2 = 4 c(x – h)
(x – h)² = 4c(y – k)
(x – h)? + y – k)²
q?
p2
(х — Һ)? —
(y – k)?
p2
q?
(x – h)? _ y – k)²
p2
q?
With
h = 100
k
= 500
p? :
= DNE
q? = DNE
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Suppose a golf ball is driven so that it travels a distance of 200 feet as measured along the ground and reaches an altitude of 500 feet. If the origin represents the tee and is the ball travels along a parabolic path over the positive x-axis, find an equation for the path of the golf ball. Which form does the equation fit? (y – k)2 = 4 c(x – h) (x – h)² = 4c(y – k) (x – h)? + y – k)² q? p2 (х — Һ)? — (y – k)? p2 q? (x – h)? _ y – k)² p2 q? With h = 100 k = 500 p? : = DNE q? = DNE

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Expert Answer

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Note that, the general form of a parabolic equation with vertex (h,k) is wwww a(x -hk, where a is real constant. y in above the equation as the value of h=100 and k = 500 Substitute y a(x-100) 500 Rewrite the equation y a(x-100) 500 as follows y a(x-100) 500 a(x-100)y500 y-500 a = (x-100) The golf ball driven in parabolic path of altitude 500 and its distance along the ground is 200 and the origin is at tee. That is, the coordinate for starting and end point of the ball will be(0,0) and (200,0)

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y-500 Substitute the coordinates (0,0) in the equation a = (x-100) 0 500 a = (0-100) 500 10000 1 20 1 in the equation y a(x-100)500 20 Substitute a= y a(x100) 500 a(x-100)y500 1 |(x-100) (y-500) 200 (x-100)20(y-500) (x-100) 4(-5)(y-500)

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