Question
Asked Sep 10, 2019
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Suppose a rock is dropped into a well 4.9 meters deep.

a) Determine the amount of time t it takes for the rock to hit the bottom of the well.

t = 


b) Determine the velocity v of the rock as it is hitting the bottom of the well.

v = 


c) If the bottom of the well is lined with thick sand so that the rock does not bounce, what is the velocity vf of the rock just after it hits the bottom of the well?

vf = 
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Expert Answer

Step 1

It is given that a piece of rock is dropped into a well which is 4.9 meters deep.

Step 2

To Find:

  • The time (t) that the rock takes to hit the bottom of the well.
  • The velocity (v) of the rock as it hits the bottom of the well.
  • The velocity (vf) of the rock just after it hits the bottom of the well, if the bottom of the well is lined with thick sand so that the rock doesn’t bounce.
Step 3

Since, it is the case of zero initial velocity. And there is positive acceleration due to gravity, because the rock is falling t...

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Image Transcriptionclose

(a) The time taken by rock to hit the bottom of the well is t(say). Using equation of motion, 1 S = ut +at 2 )r... 4.9 0() ...(.: u, = 0 and a 9.8ms2) or, 9.824.9x2 9.8 t2=-t = ±1 9.8 Ignore t-1, as time cannot be negative. So, time (t) 1 second

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