# Suppose a system returns to its original internal energy after the following changes. In step 1, 25 J of work is done on the system as it releases 37 J of heat energy. If, in step 2, the system performs 12 J of work, what is the value of q?a. 0 Jb. -24 Jc. +24 Jd. -49 Je. +49 J

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Suppose a system returns to its original internal energy after the following changes. In step 1, 25 J of work is done on the system as it releases 37 J of heat energy. If, in step 2, the system performs 12 J of work, what is the value of q?

a. 0 J

b. -24 J

c. +24 J

d. -49 J

e. +49 J

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Step 1

It is given that in first step system releases 37 J of energy which means q = -37 and the work is done on the system is 25 J.

Step 2

Hence, the change in energy of surrounding for first step is,

Step 3

In second step, it is given that system performs 12 J of work, which means the sign of work done will ...

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ScienceChemistry

### Chemical Thermodynamics 