Suppose f is a linear function and f(x) varies at a constant rate of change of 4.5 with respect to x. Suppose we know that f(1.6) = 2.5.varies from x = 1.6 to x1.7...a. Supposei. How much did x change by?Preview.1ii. What is the corresponding change in f(x)?Af(x)Preview.45iii. What is the value f(1.7)?f(1.7)Preview=2.95b. Write a function formula for f(x). (Hint: use the same thinking as in (a), but now imagine x varying from x = 1.6 to any new value of x.)f(x)Previewsyntax error

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Asked Oct 24, 2019

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Suppose f is a linear function and f(x) varies at a constant rate of change of 4.5 with respect to x. Suppose we know that f(1.6) = 2.5.
varies from x = 1.6 to x
1.7...
a. Suppose
i. How much did x change by?
Preview
.1
ii. What is the corresponding change in f(x)?
Af(x)
Preview
.45
iii. What is the value f(1.7)?
f(1.7)
Preview
=2.95
b. Write a function formula for f(x). (Hint: use the same thinking as in (a), but now imagine x varying from x = 1.6 to any new value of x.)
f(x)
Preview
syntax error
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Suppose f is a linear function and f(x) varies at a constant rate of change of 4.5 with respect to x. Suppose we know that f(1.6) = 2.5. varies from x = 1.6 to x 1.7... a. Suppose i. How much did x change by? Preview .1 ii. What is the corresponding change in f(x)? Af(x) Preview .45 iii. What is the value f(1.7)? f(1.7) Preview =2.95 b. Write a function formula for f(x). (Hint: use the same thinking as in (a), but now imagine x varying from x = 1.6 to any new value of x.) f(x) Preview syntax error

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check_circleExpert Solution
Step 1

Given, function f is a linear function. Function is varying at constant rate of change 4.5 which means

dv
= 4.5
f(1.6) 2.5
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dv = 4.5 f(1.6) 2.5

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Step 2

Let us assume

f(x)= ax+b
(1)
where a and b are constants
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f(x)= ax+b (1) where a and b are constants

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Step 3

Plugging the value of funct...

f(1.6) 1.6a+b
1.6a+b 2.5
(2)
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f(1.6) 1.6a+b 1.6a+b 2.5 (2)

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