Suppose n(X)=240n(X)=240 and XX is partitioned into six subsets X1X1, X2X2, X3X3, X4X4, X5X5, and X6X6. All assume that n(X1)=n(X2)=n(X3)n(X1)=n(X2)=n(X3) and n(X4)=n(X5)=n(X6)n(X4)=n(X5)=n(X6). If there are 3 times more elements in X1 as there are in X5, find the following values:   n(X1) n(X2) n(X3) n(X4) n(X5) n(X6)

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Polynomials

Try substituting 1. You will get 6 and not 0. Try other real values also. What About -2? Let us check.