Question

Asked Dec 19, 2019

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Suppose that 15 lightbulbs are in a cabinet and that 4 are defective. If three bulbs are chosen at random,

a. What is the probability that all three will be defective?

b. What is the probability that all three will be good?

c.Why do the probabilities from parts (a) and (b) not add up to 1?

Step 1

It is given that, 15 lightbulbs are in a cabinet and that 4 are defective.

Then, 15 - 4 = 11 lightbulbs are good.

If three bulbs are chosen at random,

a) The probability that all three will be defective is,

Step 2

b) The probability that all three will be good is,

Step 3

c) If we add the probabilities...

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