Question
Asked Nov 30, 2019
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Suppose that 25 g of each of the following substances is initially at 28.0 ∘C. What is the final temperature of each substance upon absorbing 2.40 kJ of heat?

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Express your answer to two significant figures.
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Expert Answer

Step 1

The problem is related to specific heat. It relates to heat, mass of a substance and change in temperature. Heat equation is:

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q=mCgAT 4=Heat mmassof the subs tance C Specific heat of the substance AT-Change in the temperature(T, -T)

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Step 2

Given:

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m 25g 10J - 2.40.10 kJ q2.40k and 0.240J Cs .°C

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Step 3

To determine...

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qmCsAT 0.240J 2.40*103J 25gx . ΔΤ °C 2.40x10 ΔΤ 0.240J 25gx AT 4.0x102C

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