Suppose that in a phase diagram, when the sample was prepared with the mole fraction ofcomponent A equal to 0.40 it was found that the compositions of the two phases inequilibrium corresponded to the mole fractions xAa 0.60 and xA 0.20. What is theratio of amounts of the two phases?

Question
Asked Nov 30, 2019
Suppose that in a phase diagram, when the sample was prepared with the mole fraction of
component A equal to 0.40 it was found that the compositions of the two phases in
equilibrium corresponded to the mole fractions xAa 0.60 and xA 0.20. What is the
ratio of amounts of the two phases?
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Suppose that in a phase diagram, when the sample was prepared with the mole fraction of component A equal to 0.40 it was found that the compositions of the two phases in equilibrium corresponded to the mole fractions xAa 0.60 and xA 0.20. What is the ratio of amounts of the two phases?

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Expert Answer

Step 1

The lever rule can be defined as a rule which is used for the determination of the mole fraction of each phase of a binary equilibrium phase diagram. It can also be used to estimate the fraction of the liquid and solid phases for a given binary composition and the temperature which is present between liquidus and solidus line.

Step 2

The mole fractions are given to be as follows:

KAS = 0.60
KAB= 0.20
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KAS = 0.60 KAB= 0.20

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Step 3

The mole fraction of A initially is given to be 0.40.

Using the lever rule, the ...

Amount of Alpha phase_ Mole fraction of A initially-mole fraction of A in Beta phase
Amount of Beta phase Mole fraction of A in alpha phase-mole fraction of A initially
0.4 0.2
0.6 0.4
=1
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Amount of Alpha phase_ Mole fraction of A initially-mole fraction of A in Beta phase Amount of Beta phase Mole fraction of A in alpha phase-mole fraction of A initially 0.4 0.2 0.6 0.4 =1

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