Suppose that the following probability density function (pdf) for the random variable X: f0(1 + x)-(1+) 0 1 f(r:0) = otherwise is a member of the one-parameter exponential family of the continuous type, then we have to choose the four functions p(0), k(x), S(x) and q(0) as follows: (A) p(0) = In 0, k(x) = In (1+ x), S(x) = -In (1+ x) and q(8) = 0 (B) p(@) = 0, k(x) = In (1 + x), S(x) = -In (1 + x) and q(0) = In e (C) p(@) = 0, k(x) = -In (1 + x), S(x) = In (1 + x) and q (@) = -In@ (D) p(8) = 0, k(x) = -In (1 + x), S(x) = -In (1+ x) and q(0) = Ine A C D

A First Course in Probability (10th Edition)
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Chapter1: Combinatorial Analysis
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Suppose that the following probability density function (pdf) for the random
variable X:
f(r:0) = f0(1+x)-(1+4) , 0<x< o: 8>1
otherwise
is a member of the one-parameter exponential family of the continuous type, then
we have to choose the four functions p(0), k(x), S(x) and q(0) as follows:
(A) p(@) = In 0, k(x) = In (1+ x), S(x) - -In (1+ x) and q(@) = 6
(B) p(@) = 0, k(x) = In (1 + x), S(x) = -In (1 + x) and q(0) = In 0
(C) p(@) = 0, k(x) = -In (1 + x), S(x) = In (1 + x) and q (@) = -In8
(D) p(8) = 6, k(x) =-In (1 + x), S(x) = -In (1+ x) and q(8) = In0
A
C
Transcribed Image Text:Suppose that the following probability density function (pdf) for the random variable X: f(r:0) = f0(1+x)-(1+4) , 0<x< o: 8>1 otherwise is a member of the one-parameter exponential family of the continuous type, then we have to choose the four functions p(0), k(x), S(x) and q(0) as follows: (A) p(@) = In 0, k(x) = In (1+ x), S(x) - -In (1+ x) and q(@) = 6 (B) p(@) = 0, k(x) = In (1 + x), S(x) = -In (1 + x) and q(0) = In 0 (C) p(@) = 0, k(x) = -In (1 + x), S(x) = In (1 + x) and q (@) = -In8 (D) p(8) = 6, k(x) =-In (1 + x), S(x) = -In (1+ x) and q(8) = In0 A C
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