SuSuppose that the trigonometric substitution r = 3 tan 0 is used to compute anintegral and the answer to the integral isParrerJo0+csc 0+C3/27/202Finish the problem by rewriting the answer in terms of z.01NavI+ csc x + C4[0]01[4Q2a)[4]05[4]Q6[4]Q9(4]Q 10tan (), V- 9b) O(4]Q 13(4]Q 14[0]Q 17+ CTESTINETime AlleTotal ProbTotal Pa) tan+CCOLORINx² + 9NotAnswered72+++ C

Simply use resubstitution and replace θ in terms of x from initial trigonometric substitution.

Suppose that the trigonometric substitutionx = 3 tan 0 is used to compute an integral and the answer to the integral is 1 0+csc 0+ C Finish the problem by rewriting the answer in terms of z. 1 a) 0-x + csc a + C 4 Va² - + C 1 b) Otan (), V2 9 b) 0tan 4 3 1 -tan c) +C Va? - 9 22 1 tan 4 (), d) + C V2 +9 3 1 tan 4 Vr² + 9 +C