# Suppose the mean income of firms in the industry for a year is 4545 million dollars with a standard deviation of 13 million dollars. If incomes for the industry are distributed normally, what is the probability that a randomly selected firm will earn less than 60 million dollars? Round your answer to four decimal places.

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Suppose the mean income of firms in the industry for a year is 4545 million dollars with a standard deviation of 13 million dollars. If incomes for the industry are distributed normally, what is the probability that a randomly selected firm will earn less than 60 million dollars? Round your answer to four decimal places.

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Step 1

Given information:

Step 2

Let X is random variable.

The probability that a randomly selected firm wi... help_outlineImage TranscriptioncloseX- u 60 - u P(X <60)= P --{2-) 60 – 45 = P| Z < 13 = P(Z <1.15) = 0.8749 fullscreen

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