Suppose the position of an object moving horizontally after t seconds is given by the following function s = f(t), where s is measured in feet, with s>0 corresponding positions right of the origin. a. Graph the position function. b. Find and graph the velocity function. When is the object stationary, moving to the right, and moving to the left? c. Determine the velocity and acceleration of the object at t= 1. d. Determine the acceleration of the object when its velocity is zero. e. On what intervals is the speed increasing? f(t) = t - 9t + 24t; 0sts6

College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter2: Functions
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Can you help me with parts b-e
Suppose the position of an object moving horizontally after t seconds is given by the following function s =f(t), where s is measured in feet, with s > 0 corresponding to
positions right of the origin.
a. Graph the position function.
b. Find and graph the velocity function. When is the object stationary, moving to the right, and moving to the left?
c. Determine the velocity and acceleration of the object at t = 1.
d. Determine the acceleration of the object when its velocity is zero.
e. On what intervals is the speed increasing?
f(t) = t° - 9t2 + 24t 0 sts6
As
As
40-
0-
40-
-40
0-
-40
b. v(t) =
Transcribed Image Text:Suppose the position of an object moving horizontally after t seconds is given by the following function s =f(t), where s is measured in feet, with s > 0 corresponding to positions right of the origin. a. Graph the position function. b. Find and graph the velocity function. When is the object stationary, moving to the right, and moving to the left? c. Determine the velocity and acceleration of the object at t = 1. d. Determine the acceleration of the object when its velocity is zero. e. On what intervals is the speed increasing? f(t) = t° - 9t2 + 24t 0 sts6 As As 40- 0- 40- -40 0- -40 b. v(t) =
As
40-
Ini
di
0-
0.
wer
OK
Transcribed Image Text:As 40- Ini di 0- 0. wer OK
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