Suppose the pulley absorbs a significant  fraction of the energy in the wave so that the amplitude of the reflected wave is not equal to the amplitude of the wave set up with a vibrator. How will the standing waves differ from those established under conditions of perfect reflection? Hint: Remember what happens to the nodes when you add two waves of different amplitude. Will their superposition give zero amplitude?

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Asked Apr 15, 2019
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Suppose the pulley absorbs a significant  fraction of the energy in the wave so that the amplitude of the reflected wave is not equal to the amplitude of the wave set up with a vibrator. How will the standing waves differ from those established under conditions of perfect reflection? Hint: Remember what happens to the nodes when you add two waves of different amplitude. Will their superposition give zero amplitude?

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Expert Answer

Step 1

The following two cases arise for waves generated by the perfect reflection:

 

  1. The nodes of the incident wave and the antinodes of the reflected wave coincide with each other and give zero amplitude.
  2. The nodes of the incident wave coincide with the nodes of the reflected wave and give the amplitude two times that of the incident wave.
Step 2

If the amplitude of the reflected wave is not equal to the amplitude of the wave set up with a vibrator by some absorption of the energy from the incident wave then, the amplitude of this wave is neither zero nor twice of the amplitude of incident wave rather it would lie between zero and ...

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