Asked Oct 11, 2019
  1. Suppose there are 100 students in your accounting class, 10 of whom are left-handed.


  1. Two students are drawn at random. Draw the probability tree and insert the probability for each branch.

What is the probability of the following events?


  1. Both are right-handed?
  2. Both are left-handed?
  3. One is right-handed and the other is left-handed?
  4. At least one is right-handed?

Expert Answer

Step 1

1)The letter R represents right-handed student and L represents left-handed student. The probability tree and corresponding probabilities is given below:


Image Transcriptionclose

89 RR 90 100 99 RL 90 100 99 10 X Selecting two students - 10 90 LR X 100 99 LL 10 X 100 99

Step 2

Probability of given events:

1)The probability that both student selected are right-handed is calculated as follows:


Image Transcriptionclose

90 P(Both are right-handed) = 89 X 100 99 0.80909 0.8091

Step 3

2)The probability that both student selected ar...


Image Transcriptionclose

9 P(Both are left-handed)- 10 100 99 X 0.00909 0.0091


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