Suppose there are four processes (P1 - P4) with respective arrival times of 0, 10, 30, and 40, and burst times of 30, 20, 50, and 20 ms. These processes are scheduled from a ready queue on first come first served. The average waiting time is: None of the answers 30 25 20
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- Processes P1, P2, and P2 are queued to run. The arrival time of P1 is t = 0, the arrival time of P2 is t = 1, and the arrival time of P3 is t = 2. According to the first come first serve (FCFS) algorithm, processes are run by the operating system. P1 operates 7 time units, P2 4 time units, P3 operates 1 time unit. So what is the average waiting time (in time units) for this system? 0 5 3 7in round robin when three processes have to enter the ready queue at the instant , if one process has just finished I/O the other has preempted from CPU due to expiration of its quantum and third (C) has just started. which one will be inserted last (ie lowest priority ) ? a) the process that has just finished I/O b) One of the three will be random be selected c) The process that has been pre-empted from CPU due to expiration of its quantum time. d) The process that has just startedWhat advantage is there in having different time-quantum sizes at different levels of a multilevel queueing system? Why is it important for the scheduler to distinguish I/O-bound programs from CPU-bound programs?
- Consider a system consisting of m resources of the same type being shared by n processes, n > m. Each process has a maximum need of m/2 resources. Initially, each process has no resource requests. A process can request or release only one resource at a time. With n=3k and m=2k, for some integer k, show that the system is deadlock free.Suppose that a disk drive has 40 cylinders, numbered 0 to 40. The drive is currently serving a requestat cylinder 20 (the previous request served was at cylinder 19) when the last of these requests is madewith none of these requests yet served. The queue of pending requests, in FIFO order, is 5, 25, 18, 3,39, 8, and 35. A seek takes 5ms per cylinder movement. Starting from the current head position, whatis the total distance (in cylinders) that the disk arm moves to satisfy all the pending request and alsocalculate the total seek time needed to serve these requests, for each of the following disk-schedulingalgorithms? Explain with the help of a diagram in each case. a. FCFSb. SSTFc. SCANd. LOOKSuppose that a disk drive has 5,000 cylinders, numbered 0 to 4,999. The drive is currently serving a request at cylinder 2,150, and the previous request was at cylinder 1,805. The queue of pending requests, in FIFO order, is: 2,069 1,212 2,296 2,800 544 1,618 356 1,523 4,956 3,681 Calculate the total seek time for each of the schedules TOTAL DISTANCE TOTAL SEEK TIME FCFS SSTF SCAN LOOK C-SCAN C-LOOK
- Suppose there are 8 processes in a system which are waiting to be assigned to the ready queue. The processes have the following properties. Process P1 has burst time 15, priority 6 Process P2 has burst time 12, priority 4 Process P3 has burst time 6, priority 12 Process P4 has burst time 5, priority 11 Process P5 has burst time 8, priority 9 Process P6 has burst time 9, priority 2 Process P7 has burst time 2, priority 20 Process P8 has burst time 17, priority 6 You have to use Multilevel Feedback Queue. It has three queues. The first queue takes processes with priority value from 1 to 5, the second queue takes processes with priority value of 6 to 10 and rest of the processes go to the third queue. First queue follows Round Robin Scheduling with time quantum= 4 Second queue follows Round Robin Scheduling with time quantum = 6 Third queue follows FCFC scheduling. Draw the gantt chart and calculate the average waiting time.Is it feasible for a single process to get stopped mid-execution? Justifications for your replies are required.Suppose that a disk drive has 6,000 cylinders, numbered 0 to 5999. The drive is currently serving a request at cylinder 3797, and the previous request was at cylinder 1375. The queue of pending requests, in FIFO order, is: 1589, 5474, 2104, 1350, 4336, 3678, 1697, 1780, 3794, 3982, 2508 Starting from the current head position, what is the total distance (in cylinders) that the disk arm moves to satisfy all the pending requests for each of the following disk-scheduling algorithms? Show the calculation result Show the sequence of the position of the head and calculation steps 1. SSTF 2. SCAN
- There are two methods available for terminating processes and, accordingly, overcoming deadlocks:Can a single-threaded process deadlock by itself? Please elaborate on your answer.The following is the expected sequence of events when a child process reads the message buffer of its parent process using unnamed pipes.