Asked Oct 18, 2019

Suppose 7.60 g  of CH4 is allowed to burn in the presence of 16.90 g  of oxygen. 


How much (in grams) CH4 remains after the reaction is complete?


Expert Answer

Step 1

The required balanced equation is given below.


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CH, (g)20, (g)Co, (g)+2H20(g)

Step 2

From the above balanced chemical equation, it can be stated that 1 mole of CH4 is reacting with 2 mole of...


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7.60g Mass 0.4738mol Actualmoles of CH Molecularmass 16.04g /mol 16.90g Mass Actualmoles of O2 0.528 1mol Molecular mass 32g/mol


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