Question
Asked Jun 11, 2019
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In the figure particle 1 of charge +6e is above a floor by distance d1 = 3.60 mm and particle 2 of charge +7e is on the floor, at distance d2 = 8.60 mm horizontally from particle 1. What is the xcomponent of the electrostatic force on particle 2 due to particle 1?

 

T
di
-dg
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T di -dg

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Expert Answer

Step 1

Its given that:

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91 3 бе — 6 х 1.6 х 10-19 С 92 3D 7е — 7 х 1.6 х 10-19C d, 3 3.6 тm dz 3D 8.6 тm

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Step 2

The distance (d3) from particle 1 to particle 2 will be:

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Particle 1 d3 d2 Particle 2 e F cose х-аxis d1 F d3 |(3.6)2 (8.6)2 d3 9.32 mm

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Step 3

The force (F) on particle 2 due...

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kq1q2 F = d2 9х 10° х бех 7е (9.32 х 10-з)2 F%3D 1.114 х 10-22 N

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