Question
Asked Dec 2, 2019
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The figure shows a box of mass m = 5.50 kg pulled to the right across a horizontal surface by a constant tension force of magnitude T = 28.0 N. The tension force is inclined at an angle θ = 18.0° above the horizontal and the friction force has magnitude fk = 12.5 N.The box is pulled a distance d = 1.70 m.

 

Determine the work done on the box by the tension force, the normal force, and the kinetic friction force. We'll use WT,Wn, and Wfk to represent the magnitudes of the tension, normal, and friction forces, respectively

T
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T

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Expert Answer

Step 1

The work done due to tension force is,

w(Tcosd)cosa
-28cas(18)1.7)cas(0)
45.27J
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w(Tcosd)cosa -28cas(18)1.7)cas(0) 45.27J

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Step 2

The work done due to n...

wy Ndcos(90)
=0J
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wy Ndcos(90) =0J

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