Question
Asked Jul 9, 2019
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differentiate f(t) = t^(1/3)/ (t-3) On the solution guide on the first step for the numerator, we have for the last t, t^(1/3) and on the second step we end up getting for that same t on the numerator a t^ (3-2)/3 where does the 3 even come from?

(t-3)2
Simplify the numerator,
-2
1- 3-3
3-2
f' ()
t-3)2
2
3 -3-3 t
2
(f-3)2
(1-3)
LG+-)-1]
(t-3)2
t 3
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(t-3)2 Simplify the numerator, -2 1- 3-3 3-2 f' () t-3)2 2 3 -3-3 t 2 (f-3)2 (1-3) LG+-)-1] (t-3)2 t 3

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Step 1

Explanation:

Consider the term t1/3.

It is known that adding and subtracting a same number to any number does not change its originality.

So add and subtra...

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1+1 t3t3 1-3+3 Taking LCM] =t 3 (1-3)+3 =t (-2)+3 re

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Calculus

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