(t-3)2 Simplify the numerator, -2 1- 3-3 3-2 f' () t-3)2 2 3 -3-3 t 2 (f-3)2 (1-3) LG+-)-1] (t-3)2 t 3
differentiate f(t) = t^(1/3)/ (t-3) On the solution guide on the first step for the numerator, we have for the last t, t^(1/3) and on the second step we end up getting for that same t on the numerator a t^ (3-2)/3 where does the 3 even come from?
![(t-3)2
Simplify the numerator,
-2
1- 3-3
3-2
f' ()
t-3)2
2
3 -3-3 t
2
(f-3)2
(1-3)
LG+-)-1]
(t-3)2
t 3](https://prod-qna-question-images.s3.amazonaws.com/question/dc938dad-da2c-4dbc-b229-ff2e33684649/2e404f9a-e80d-467e-a21c-b83a19fc517d/mcfdhpc.png)
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(t-3)2 Simplify the numerator, -2 1- 3-3 3-2 f' () t-3)2 2 3 -3-3 t 2 (f-3)2 (1-3) LG+-)-1] (t-3)2 t 3
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