differentiate f(t) = t^(1/3)/ (t-3) On the solution guide on the first step for the numerator, we have for the last t, t^(1/3) and on the second step we end up getting for that same t on the numerator a t^ (3-2)/3 where does the 3 even come from?

Simplify the numerator,
1- 3-3
f' ()
3 -3-3 t
t 3

Image Transcription

(t-3)2 Simplify the numerator, -2 1- 3-3 3-2 f' () t-3)2 2 3 -3-3 t 2 (f-3)2 (1-3) LG+-)-1] (t-3)2 t 3

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