Question
Asked Nov 12, 2019
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This is one question with multiple parts

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Table 1
Time
Displacement
(cm)
Average velocity
(cm/interval)
Total displacement
(cm)
(interval)
1
CM
Cm
2
CM
2.2
4.2
2.2 Cm
3
2.2
2 2 Cm
G.4
cM
4
2.2
2.2 Cm
2.6
CnM
5
2.4
2.4 Cm
Cm
6
2.4
2.4 cm
13.4
СМ
7
2.5cm
2.5
15.9
CM
2.4 cm
2.4
8.3
Cm
9
2.6
2.6 cm
Cm
20.4
Cm
10
2.6cm
23.5
2.6
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Table 1 Time Displacement (cm) Average velocity (cm/interval) Total displacement (cm) (interval) 1 CM Cm 2 CM 2.2 4.2 2.2 Cm 3 2.2 2 2 Cm G.4 cM 4 2.2 2.2 Cm 2.6 CnM 5 2.4 2.4 Cm Cm 6 2.4 2.4 cm 13.4 СМ 7 2.5cm 2.5 15.9 CM 2.4 cm 2.4 8.3 Cm 9 2.6 2.6 cm Cm 20.4 Cm 10 2.6cm 23.5 2.6

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Expert Answer

Step 1

Given:

Using the given data we can draw v-t graph,

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Table 1 Time interval) Displacement (cm) Average velocity (cm/interval) Total displacement (cm) Cm 2 2-2 4-2 CM 2.2 Cm 2.2 2-2 C 6.4 CM 2-2 2-2 cm 8-6 Cn 2-4 2-4 cm 11 Cm 6 2-4 2-4 Cm 13.4 CM 7 2-5 2-5cm 15.9 CM 8 2.4 cm 2-4 I8.3 Cm 2.6 2-6 cm Cm 20-4 10 Cm 2-6cm 23-5 2-6 n

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Step 2

Part (a):

Area under the line of v-t graph is equal to displacement done during given interval of time,

Graph for v-t can be shown below,

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1 2.5 1.5 0.5 20 20

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Step 3

Part (b):

Area under the curve in differen...

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x2x1=2 d 2+2.2x1=4.2 d 2+2.2x2 6.4 d 2+2.2x3=7.6 d, 2+2.2x3+2.4x1=11 dg 2+2.2x3+2.4x2=13.4 d, 2+2.2x3+2.4x2+2.5x1=15.9 d 2+2.2x3+2.4x2+2.5x1+2.4x1=18.3 d 2+2.2x3+2.4x2+2.5x1+2.4x1+2.6x1=20.9 do2+2.2x3+2.4x2+2.5x1+2.4x1+2.6x1+2.6x2= 23.5

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