Test the claim that the proportion of people who own cats is significantly different than 80% at the0.02 significance level.The null and alternative hypothesis would be:Ho:µ < 0.8 Ho:p< 0.8 Ho:µ > 0.8 Ho:p= 0.8 Ho:µ = 0.8 Ho:p > 0.8H1:µ > 0.8 H1:p > 0.8 H1:µ < 0.8 H1:p 0.8 H1:µ + 0.8 H1:p < 0.8The test is:two-tailed right-tailed left-tailedBased on a sample of 100 people, 84% owned cats(to 2 decimals)The p-value is:Based on this we:Fail to reject the null hypothesisReject the null hypothesis

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Asked Dec 5, 2019
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Test the claim that the proportion of people who own cats is significantly different than 80% at the
0.02 significance level.
The null and alternative hypothesis would be:
Ho:µ < 0.8 Ho:p< 0.8 Ho:µ > 0.8 Ho:p= 0.8 Ho:µ = 0.8 Ho:p > 0.8
H1:µ > 0.8 H1:p > 0.8 H1:µ < 0.8 H1:p 0.8 H1:µ + 0.8 H1:p < 0.8
The test is:
two-tailed right-tailed left-tailed
Based on a sample of 100 people, 84% owned cats
(to 2 decimals)
The p-value is:
Based on this we:
Fail to reject the null hypothesis
Reject the null hypothesis
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Test the claim that the proportion of people who own cats is significantly different than 80% at the 0.02 significance level. The null and alternative hypothesis would be: Ho:µ < 0.8 Ho:p< 0.8 Ho:µ > 0.8 Ho:p= 0.8 Ho:µ = 0.8 Ho:p > 0.8 H1:µ > 0.8 H1:p > 0.8 H1:µ < 0.8 H1:p 0.8 H1:µ + 0.8 H1:p < 0.8 The test is: two-tailed right-tailed left-tailed Based on a sample of 100 people, 84% owned cats (to 2 decimals) The p-value is: Based on this we: Fail to reject the null hypothesis Reject the null hypothesis

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Expert Answer

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Step 1

Here, the claim is that the proportion of people who own cats is significantly different than 80%.

The test hypotheses are given below:

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Null hypothesis: H,:p=0.80 Alternative hypothesis: H,:p±0.80

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Step 2

cats is significantly different than 80%. That is, the alternative hypothesis state no direction. Moreover, “≠” symbol in alternative hypothesis. Hence, the test is two-tailed test.

The test statistic is obtained as follows:

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Sample statistic – Null Parameter SE p- Po P.(1- P.) п 0.84 – 0.80 0.80(1– 0.80) 100

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Step 3

Thus, the test statistic is 1.

p-value:

Step-by-step procedure to obtain the p-value using MINITAB:

  • Choose Graph > Probability Distribution Plot choose View Probability > OK.
  • From Distribution, choose ‘Normal’ distribution.
  • Click the Shaded Area
  • Choose X-value and Both Tail for the region of the curve to shade.
  • Enter the d...
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Distribution Plot Normal, Mean=0, StDev=1 0.4 0.3 0.2 0.1- 0.1587 0.1587 0.0 -1 Density

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