Question

The 10th percentile implies that the probability is 0.1.

P[X−μσ<x−30030]=0.1P[Z<x−30030]=0.1⇒x−30030=−1.28 (Use standard normal table)⇒x=(30×−1.28)+300⇒x=261.6PX-μσ<x-30030=0.1PZ<x-30030=0.1⇒x-30030=-1.28 (Use standard normal table)⇒x=30×-1.28+300⇒x=261.6

The value of x is 261.6.

Please show me where on the table you got -1.28.  I cannot find that value on the table anywhere?  Thanks.

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