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Name: The 10th percentile implies that the probability is 0.1.P[X−μσ<x−30030
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Description: The 10th percentile implies that the probability is 0.1.P[X−μσ<x−30030]=0.1P[Z<x−30030]=0.1⇒x−30030=−1.28 (Use standard normal table)⇒x=(30×−1.28)+300⇒x=261.6PX-μσ<x-30030=0.1PZ<x-30030=0.1⇒x-30030=-1.28 (Use standard normal table)⇒x=30×-1.28+300⇒x=2

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The 10th percentile implies that the probability is 0.1. P[X−μσ

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter10: Statistics

Section10.1: Measures Of Center

Problem 9PPS

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Question

The 10th percentile implies that the probability is 0.1.

P[X−μσ<x−30030]=0.1P[Z<x−30030]=0.1⇒x−30030=−1.28 (Use standard normal table)⇒x=(30×−1.28)+300⇒x=261.6PX-μσ<x-30030=0.1PZ<x-30030=0.1⇒x-30030=-1.28 (Use standard normal table)⇒x=30×-1.28+300⇒x=261.6

The value of x is 261.6.

Please show me where on the table you got -1.28. I cannot find that value on the table anywhere? Thanks.

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