The 20kg block is subjected to the action of the harmonic force F=90cos6t N, where t is in seconds. If c=125 N.s/m and k=800 N/m, calculate the steady state vibration amplitude for the block F=90cos6t N m Base The response for the block is a sine harmonic function and its amplitude is 0.458 m

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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m
Base
The response for the block is a
sine harmonic function and its
amplitude is 0.458 m
The response for the block is a
cosine harmonic function and its
amplitude is 0.019 m
The response for the block is a
cosine harmonic function and its
amplitude is 1.56 m
The response for the block is a
cosine harmonic function and its
amplitude is 0.119 m
Transcribed Image Text:m Base The response for the block is a sine harmonic function and its amplitude is 0.458 m The response for the block is a cosine harmonic function and its amplitude is 0.019 m The response for the block is a cosine harmonic function and its amplitude is 1.56 m The response for the block is a cosine harmonic function and its amplitude is 0.119 m
The 20kg block is
subjected to the action
of the harmonic force
F=90cos6t N, where t
is in seconds. If c=125
N.s/m and k-800 N/m,
calculate the steady
vibration
state
amplitude for the block.
F=90cos6t N
m
Base
The response for the block is a
sine harmonic function and its
amplitude is 0.458 m
Transcribed Image Text:The 20kg block is subjected to the action of the harmonic force F=90cos6t N, where t is in seconds. If c=125 N.s/m and k-800 N/m, calculate the steady vibration state amplitude for the block. F=90cos6t N m Base The response for the block is a sine harmonic function and its amplitude is 0.458 m
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