The aluminum in a 1.2 g sample of impure ammonium aluminum sulfate was precipitated with aqueous ammonia. The precipitate was filtered and ignited at 1000 oC to give anhdrous Al2O3, which weighed 0.1798 g. Express the result of this analysis in terms of % NH4Al(SO4)2 and % Al2O3 (Molar mass of Al2O3 =101.96 g/mol, Molar mass of NH4Al(SO4)2= 237.15 g/mol)

Calculate the number of moles of Al2O3. Number of moles = Given mass Molar mass = 0.1798 g101.96…

Answered: The aluminum in a 1.2 g sample of…

Chemistry & Chemical Reactivity

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Problem 2.1ACP: Assume that a sample of hard water contains 50. mg/L of Mg2+ and 150 mg/L of Ca2+, with HCO3 as the...

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The aluminum in a 1.2 g sample of impure ammonium aluminum sulfate was precipitated with aqueous ammonia. The precipitate was filtered and ignited at 1000^oC to give anhdrous Al₂O₃, which weighed 0.1798 g. Express the result of this analysis in terms of % NH₄Al(SO₄)₂ and % Al₂O₃ (Molar mass of Al₂O₃ =101.96 g/mol, Molar mass of NH₄Al(SO₄)₂= 237.15 g/mol)

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