The area bounded by x = y² - 2 and x = e between y = -1 and y = 1 is revolved about the line y = 1. The Volume integral for the solid generated is O 2π ¹₁ (1-y) (y2² - 2 - e³) dy O 2π f₁y (e" - y² + 2) dy ○ 2π ¹₁ (1 - y) (e¹. y² + 2) dy ○ 2π f¹₁ (1 - y) (y² — 2 — e³) dy

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
6th Edition
ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
Publisher:Bruce Crauder, Benny Evans, Alan Noell
ChapterA: Appendix
SectionA.2: Geometric Constructions
Problem 10P: A soda can has a volume of 25 cubic inches. Let x denote its radius and h its height, both in...
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The
area bounded by x = y² 2 and x = e between y = -1 and y = 1 is revolved about the line y = 1.
The Volume integral for the solid generated is
O 2π f¹₁ (1-y) (y² — 2 — e¹) dy
○ 2π ¹₁ y (e" - y² + 2) dy
○ 2π ¹₁ (1 - y) (e" − y² + 2) dy
-1
○ 2π f¹₁ (1 - y) (y² — 2 — e³) dy
Transcribed Image Text:The area bounded by x = y² 2 and x = e between y = -1 and y = 1 is revolved about the line y = 1. The Volume integral for the solid generated is O 2π f¹₁ (1-y) (y² — 2 — e¹) dy ○ 2π ¹₁ y (e" - y² + 2) dy ○ 2π ¹₁ (1 - y) (e" − y² + 2) dy -1 ○ 2π f¹₁ (1 - y) (y² — 2 — e³) dy
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