Asked Oct 25, 2019

The atomic masses of 10B and 11B are 10.0129 amu and 11.0093 amu, respectively. Calculate the natural abundances of these two isotopes. The average atomic mass of B is 10.811 amu.
10B = 

11B = 




Expert Answer

Step 1

The atomic masses of B10 and B11 are 10.0129 and 11.0093 respectively

Let their natural abundances be x and y





Step 2

The average mass of...


Image Transcriptionclose

(10.0129)x + (11.0093) (1-x)=10.811 10.0129x11.0093-11.0093x 10.811 0.9964.x 0.1983 x 0.1990


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