Question
Asked Oct 25, 2019
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The atomic masses of 10B and 11B are 10.0129 amu and 11.0093 amu, respectively. Calculate the natural abundances of these two isotopes. The average atomic mass of B is 10.811 amu.
 
10B = 

11B = 

 

 

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Expert Answer

Step 1

The atomic masses of B10 and B11 are 10.0129 and 11.0093 respectively

Let their natural abundances be x and y

Where

x+y=1

therefore,

y=1-x

Step 2

The average mass of...

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(10.0129)x + (11.0093) (1-x)=10.811 10.0129x11.0093-11.0093x 10.811 0.9964.x 0.1983 x 0.1990

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