The body mass of a certain type of sheep can be estimated by M(t) = 26.80.3t-0.001t where M(t) is measured in kilograms and t is days since May 25. a. Find the average rate of change of the mass of a sheep between 105 and 114 days past May 25. b. Find the instantaneous rate of change of the mass of a sheep whose age is 105 days past May 25. c. Graph the function M(t) on [5, 125] by [25, 65] d. Does the behavior of the function past 125 days accurately model the mass of the sheep? Why or why not? M(114)- M(105) M(114)-M(105) О В. A 105 114 М(114) - М(105) M(114) M105) c. O D 114 105 114 105 The average rate of change of the mass of the sheep between days 105 and 114 is081 kg per day. (Type an integer or a decimal.) b. Which of the following is a correct expression for the instantaneous rate of change on day 105? M(105 h) M(105 h) lim M(105 h) M(h) lim A O B. h 0 105 h h 0 M(105 h) M(105) M(105 h) M(105) lim O C. lim 105 h 0 h0 The instantaneous rate of change of the mass of the sheep whose age is exactly 105 days past May 25 is (Type an integer or a decimal.)
The body mass of a certain type of sheep can be estimated by M(t) = 26.80.3t-0.001t where M(t) is measured in kilograms and t is days since May 25. a. Find the average rate of change of the mass of a sheep between 105 and 114 days past May 25. b. Find the instantaneous rate of change of the mass of a sheep whose age is 105 days past May 25. c. Graph the function M(t) on [5, 125] by [25, 65] d. Does the behavior of the function past 125 days accurately model the mass of the sheep? Why or why not? M(114)- M(105) M(114)-M(105) О В. A 105 114 М(114) - М(105) M(114) M105) c. O D 114 105 114 105 The average rate of change of the mass of the sheep between days 105 and 114 is081 kg per day. (Type an integer or a decimal.) b. Which of the following is a correct expression for the instantaneous rate of change on day 105? M(105 h) M(105 h) lim M(105 h) M(h) lim A O B. h 0 105 h h 0 M(105 h) M(105) M(105 h) M(105) lim O C. lim 105 h 0 h0 The instantaneous rate of change of the mass of the sheep whose age is exactly 105 days past May 25 is (Type an integer or a decimal.)
Chapter6: Exponential And Logarithmic Functions
Section6.1: Exponential Functions
Problem 60SE: The formula for the amount A in an investmentaccount with a nominal interest rate r at any timet is...
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![The body mass of a certain type of sheep can be estimated by M(t) = 26.80.3t-0.001t where M(t) is measured in kilograms and t is days since May 25.
a. Find the average rate of change of the mass of a sheep between 105 and 114 days past May 25.
b. Find the instantaneous rate of change of the mass of a sheep whose age is 105 days past May 25.
c. Graph the function M(t) on [5, 125] by [25, 65]
d. Does the behavior of the function past 125 days accurately model the mass of the sheep? Why or why not?
M(114)- M(105)
M(114)-M(105)
О В.
A
105
114
М(114) - М(105)
M(114) M105)
c.
O D
114 105
114
105
The average rate of change of the mass of the sheep between days 105 and 114 is081
kg per day.
(Type an integer or a decimal.)
b. Which of the following is a correct expression for the instantaneous rate of change on day 105?
M(105 h) M(105 h)
lim
M(105 h) M(h)
lim
A
O B.
h 0
105
h
h 0
M(105 h) M(105)
M(105 h) M(105)
lim
O C. lim
105
h 0
h0
The instantaneous rate of change of the mass of the sheep whose age is exactly 105 days past May 25 is
(Type an integer or a decimal.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6e2c5a88-a31f-4e9d-bcbd-75e956d26fb0%2F9700d113-f4e9-4977-b724-ba5d0af66cbe%2Fq6xd40l.png&w=3840&q=75)
Transcribed Image Text:The body mass of a certain type of sheep can be estimated by M(t) = 26.80.3t-0.001t where M(t) is measured in kilograms and t is days since May 25.
a. Find the average rate of change of the mass of a sheep between 105 and 114 days past May 25.
b. Find the instantaneous rate of change of the mass of a sheep whose age is 105 days past May 25.
c. Graph the function M(t) on [5, 125] by [25, 65]
d. Does the behavior of the function past 125 days accurately model the mass of the sheep? Why or why not?
M(114)- M(105)
M(114)-M(105)
О В.
A
105
114
М(114) - М(105)
M(114) M105)
c.
O D
114 105
114
105
The average rate of change of the mass of the sheep between days 105 and 114 is081
kg per day.
(Type an integer or a decimal.)
b. Which of the following is a correct expression for the instantaneous rate of change on day 105?
M(105 h) M(105 h)
lim
M(105 h) M(h)
lim
A
O B.
h 0
105
h
h 0
M(105 h) M(105)
M(105 h) M(105)
lim
O C. lim
105
h 0
h0
The instantaneous rate of change of the mass of the sheep whose age is exactly 105 days past May 25 is
(Type an integer or a decimal.)
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