The can of soda reaches the temperature of 50°F after 25 minutes. Using this information, find the value of k, to the nearest thousandth. Use the resulting equation to determine the Fahrenheit temperature of the can of soda, to the nearest degree, after 60 minutes. Enter only the final temperature into the input box.
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- This exercise uses Newton's Law of Cooling. A hot bowl of soup is served at a dinner party. It starts to cool according to Newton's Law of Cooling so that its temperature at time t is given byT(t) = 62 + 142e−0.05twhere t is measured in minutes and T is measured in °F. (a) What is the initial temperature of the soup? °F (b) What is the temperature after 10 min? (Round your answer to one decimal place.) °F (c) After how long will the temperature be 100°F? (Round your answer to the nearest whole number.)Some amount of heat energy is removed from a 10cm X 20cm X 43cm block of ice to cool from 0°C to -38°C. (Hint: to find mass, use the relation between, density, mass and volume) Calculate the following: a) The mas of ice cube in grams (density of ice = 920 kg/m³). b) The temperature difference in kelvin C) The energy removed from ice in calories . (specific heat of ice = 2093 J/kg°C)After sitting out of a refrigerator for a while, a turkey at room temperature (72^\circ72∘F) is placed into an oven. The oven temperature is 315^\circ315∘F. Newton's Law of Heating explains that the temperature of the turkey will increase proportionally to the difference between the temperature of the turkey and the temperature of the oven, as given by the formula below: T=T_a+(T_0-T_a)e^{-kt}T=Ta+(T0−Ta)e−kt T_a=Ta= the temperature surrounding the objectT_0=T0= the initial temperature of the objectt=t= the time in hoursT=T= the temperature of the object after tt hoursk=k= decay constant The turkey reaches the temperature of 136^\circ136∘F after 2 hours. Using this information, find the value of kk, to the nearest thousandth. Use the resulting equation to determine the Fahrenheit temperature of the turkey, to the nearest degree, after 6 hours. Enter only the final temperature into the input box.
- Newton's Law of Cooling The temperature of a cup of coffee t min after it is poured is given by the following equation where T is measured in degrees Fahrenheit. T = 65 + 110e−0.053t (a)What was the temperature (in degrees Fahrenheit) of the coffee when it was poured?_________ °F (b)When (in minutes) will the coffee be cool enough to drink (say, 120°F)? (Round your answer to one decimal place.)_______ minNewton's Law of Cooling The temperature of a cup of coffee t min after it is poured is given by the following equation where T is measured in degrees Fahrenheit. T = 65 + 90e−0.068t (a) What was the temperature (in degrees Fahrenheit) of the coffee when it was poured? ____ °F (b) When (in minutes) will the coffee be cool enough to drink (say, 120°F)? (Round your answer to one decimal place.) ______minAccording to Newton's law of cooling, the temperature of an object changes at a rate proportional to the difference in temperature between the object and the outside medium. If an object whose temperature is 70°F is placed in a medium whose temperature is 20 and is found to be 40" after 3 min, what will its temperature be after 6 min?
- Newton’s law of cooling says that the temperature of a body changes at a rate proportional to the difference between its temperature and that of the surrounding medium (the ambient temperature),In Exercises 5-12, use Newton's Law of Cooling A hot anvil with cooling constant k = 0.02 s- 1 is submerged in a largepool of water whose temperature is 10°C. Let y(t) be the anvil's temperature t seconds later.(a) What is the differential equation satisfied by y(t)?(b) Find a formula for y(t), assuming the object's initial temperature is100°c.(c) How long does it take the object to cool down to 20°?One 500mL glass of coke is 10°C when 0°C ice is added to the glass. After enough time, all the ice has melted and the liquid in the glass is now 8°C. How heavy was the ice? (l = water = 333 · 103 J/kg, specific heat for coke ≈ water = 4186 J/kgK) My answer is 11,4 grams but the book says 124 g?
- How much energy is required to convert 0.10 kg of water at 100∘C to steam at 100∘C? Heat of vaporization at the boiling temperature for water is Lv = 2.256E6 J/kg Express your answer to two significant figures and include the appropriate units.1. Add of 0.724 and 0.15 following the rules for significant figures. a. 0.9 b. 1 c. 0.87 d. 0.874 2. An example of physical quantity is a. Universal Law of Gravitation b. Coulombs Law c. Newton’s Law of Motion d. Height 3. Liquid nitrogen is often used to perform entertaining low-temperature physics demonstrations. Nitrogen gas liquifies at a temperature of -346 degrees Fahrenheit. What is its temperature in degrees celsius? a. 100 degrees Celsius b. 63 degrees Celsius c. 1000 degrees Celsius d. -210 degrees CelsiusNewton’s law of cooling describes the temperature T of a body cooling down to the surrounding temperature T0. T and T0 are related through the equation: dT = -k (T - T0), where k>0. dt Formulate an expression for T in terms of k and T0. A body of length L0 when heated causes a linear expansion of the body to a new length L. dL = aL, where a>0. dT Formulate an expression for L in terms of a and L0.