Question
Asked Oct 26, 2019

The combustion of octane, C8H18, proceeds according to the reaction shown. 2C8H18(l) + 25O2(g) --> 16CO2(g) 18H2O(l). If 5.30 x 10^2 mol of octane combusts, what volume of carbon dioxide is produced at 10 C and 0.995 atm?

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Expert Answer

Step 1
adaue is dhorm
The reaction o
belori
the combustion
18H,0u)
2C He )250 9-> 16c0,)+
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adaue is dhorm The reaction o belori the combustion 18H,0u) 2C He )250 9-> 16c0,)+

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Step 2
octaue produce 16 moles c Thereoe
producad by 530
2 moles
octauce
x10 Ol
co
s calculated as
amount
octance
2 mok
Mole
octauce
actane
CO2
2
424 x 0 mole
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octaue produce 16 moles c Thereoe producad by 530 2 moles octauce x10 Ol co s calculated as amount octance 2 mok Mole octauce actane CO2 2 424 x 0 mole

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Step 3
0११S atw
P
o082 Latm/kmol"
R
lot 273
T
283K
42- 410 MoL
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0११S atw P o082 Latm/kmol" R lot 273 T 283K 42- 410 MoL

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