Asked Dec 9, 2019

The combustion of octane, C8H18, proceeds according to the reaction shown.


If 538 mol of octane combusts, what volume of carbon dioxide is produced at 23.0 ∘C and 0.995 atm?


Expert Answer

Step 1

From the balanced equation, it is clear that two moles of octane react to give 16 moles of carbon dioxide.



Image Transcriptionclose

2 C,H1, (1)+ 25 O,(g)→16 CO, (g)+18 H,O(1) 16 CO, No. of mol of CO, = 538 mol C,H, x- 2 CH18 = 4304 mol CO,


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