The cube in the figure has sides of length L = 10.0 cm. The electric field is uniform, has a magnitude E = 4.00 × 10³ N/C, and is parallel to the xy-plane at an angle of 36.9° measured from the +x – axis toward the +y – axis. S2 (top) S, (back) S- (left side) L - S3 (right side) y S4 (bottom) S5 (front) Part A What is the electric flux through the cube face S1? ANSWER: P1 = N.m² /C Part B What is the electric flux through the cube face S2? ANSWER: P2 = N·m² /C Part C What is the electric flux through the cube face S3?

Physics for Scientists and Engineers
10th Edition
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter23: Continuous Charge Distributions And Gauss's Law
Section: Chapter Questions
Problem 32P: Assume the magnitude of the electric field on each face of the cube of edge L = 1.00 m in Figure...
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The cube in the figure has sides of length L = 10.0 cm. The electric field is uniform, has a magnitude E = 4.00 × 10³ N/C, and is parallel to the xy-plane at an angle of 36.9° measured from the +x – axis
toward the +y – axis.
S2 (top)
S, (back)
S-
(left side)
L
- S3 (right side)
y
S4 (bottom)
S5 (front)
Part A
What is the electric flux through the cube face S1?
ANSWER:
P1 =
N.m² /C
Part B
What is the electric flux through the cube face S2?
ANSWER:
P2 =
N·m² /C
Part C
What is the electric flux through the cube face S3?
Transcribed Image Text:The cube in the figure has sides of length L = 10.0 cm. The electric field is uniform, has a magnitude E = 4.00 × 10³ N/C, and is parallel to the xy-plane at an angle of 36.9° measured from the +x – axis toward the +y – axis. S2 (top) S, (back) S- (left side) L - S3 (right side) y S4 (bottom) S5 (front) Part A What is the electric flux through the cube face S1? ANSWER: P1 = N.m² /C Part B What is the electric flux through the cube face S2? ANSWER: P2 = N·m² /C Part C What is the electric flux through the cube face S3?
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