X- 36.0009-1.456Step 3. After compleling the table, present following computations and the interpretation.Calculate the correlation coetticient Ir). using the working formula:o The sign or integer before the value just interprets the value as either directly or inversely proportional. Just consider the rounded-off value il it isequal to I or 0.o If the computedr>0, it means that there is a perfect correlation between the variables. Therefore, there will be a need to continue solving forthe slope and y intercept, No further calculations will be made it r Linear RegressionThe data given below indicate the existence of a linear relationship between the x and y variables. Suppose an analyst who prepared the solutions and carriedout the RI measurements was not skilled and as a result of poor technique, ollowed intemediate errors to appear. The resuts are the following:Concentration of solution in percent1026335061Refractive indices (y)1.4971.4931.4851.4781.477Step 1. Carefully piot the given x and y values (from the table) on a regular graphing paper (or milimeter graphing poper - it available, preferred for precision).Label then connect the points to observe a zigzag plot due to the scattered points.Step 2. Copy and fill the given table (belowjon the top part of your graphing paper, atter your student details to commence with linear regression. For unifomity.ALL computed values to be filed in this table will be rounded-off to the 3rd decimal place. The values obtained in this table are REAL numbers (with either positiveor negative integers), to be included in the summation for each column. For answers with exponents, copy the base number in decimal form up to the 3 decimalploce then add the "x10" (example: 1.234 x 10). Since this is a guided quiz, I have included some answers (in red ink) to help you through the activity, Rormember."there is no shortcut to success". Doubie check answers before proceeding.(y - 9)0.011(x - x) (y-9)(x - X)(x - X)2(y-9)21.210x104-0.286y10-26.000676.0001.497261.493331.485501.478611.477Σ-180.000 | ΣΣ-7.430*- Exi +N- Evi +N= 36.000= 1.486

"Since you have posted a question with multiple sub-parts, we will solve the first three sub-parts…

The data given below indicate the existence of a linear relationship between thex and y variables. Suppose an analyst who prepared the solutions and coried out the RI measurements was not skilled and as a result of poor technique, allowed intemediate errors to appear. The resuits are the following Concentration of solution in percent ( 10 26 33 50 61 Refractive indices ty) 1.497 1.493 1.485 1478 1.477 Step 1. Carefully piot the given x and y values (from the tabie) on a regular graphing paper (or milimeter graphing poper - it avaiable, preferred for precision). Label then connect the points to observe a zigzog plot due to the scattered points. Slep 2. Copy and fil the given table (belowjon the top part of your grophing paper, after your student detais to commence with inear regression. For uniformity, ALL computed values to be filed in this tabie wil be rounded-off to the 3 decimal place. The values obtained in this table are REAL numbers with either positive or negative integers). to be included in the summation for each column. For answers withexponents, copy the base number in decimal form up to the 3 decimal ploce then add the "x10" (example: 1.234x 10). Since this is a guided quiz. Ihave included some answers in red ink) to help you through the activity, Remember. "there is no shortcut to success". Double check answers before proceeding (x - X) (x - X)2 676.000 (y - 9) 0.011 (y - 9) 1.210x104 (x - X) (y - ý) 10 -26.000 1.497 -0.286 26 1.493 33 1.485 50 1.478 61 1.477 E= 180.000 E= E=7.430 Σ -EviN =36.000

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter5: Inverse, Exponential, And Logarithmic Functions

Section5.6: Exponential And Logarithmic Equations

Problem 53E