The data in the table below presents the hourly quantity of production for three lines of production processes over the first 4 days in XYZ Company. Answer the questions based on the Excel Output given below.   Day Process 1 Process 2 Process 3 1 33 33 28 2 30 35 36 3 28 30 30 4 29 38 34   ANOVA: Single Factor SUMMARY Groups Count Sum Average Variance Process 1 4 120 30 4.66667 Process 2 4 136 34 11.3333 Process 3 4 128 32 13.3333   ANOVA Source of Variation SS df MS f P-value Between groups 32 ? ? ?   Within groups 88 ? ?     Total 120 11           State the null and alternative hypothesis for single factor ANOVA. State the decision rule (α = 0.05). Calculate the test statistic. Make a decision.

The Precision Machining Company makes hand-held tools on an assembly line that produces one product every minute. On one of the products, the critical quality dimension is the diameter (measured in thousandths of an inch) of a hole bored in one of the assemblies. Management wants to detect any shift in the process average diameter from 0.010 in. Management considers the variance in the process to be in control. Historically, the average range has been 0.002 in., regardless of the process average. Design an x-chart to control this process, with a center line at 0.010 in. and the control limits set at three sigmas from the center line. Management provided the results of 80 minutes of output from the production line, as shown in the table below. During these 80 minutes, the process average changed once. All measurements are in thousandths of an inch. Sample data for Precision Machining Company Diameter (thousandths of an inch) Minutes 1- 12 10 11 13 11 12 10 9. 8 11 12 13 - 24 10 11 12 11…

what does MS stand for in analysis of variance?

The data in the table below presents the hourly quantity of production for three lines of productionprocesses over the first 4 days in XYZ Company. Answer the questions based on the Excel Output givenbelow.Day  Process 1    Process 2    Process 31        33               33                 282        30                35                363        28               30                 304        29                38                34 ANOVA: Single FactorSUMMARYGroups         Count      Sum        Average                  VarianceProcess 1        4            120            30                      4.66667Process 2        4            136            34                      11.3333Process 3        4             128           32                       13.3333 ANOVSource of Variation      SS      df     MS      F       P valueBetween Groups          32       ?       ?         ?Within Groups              88       ?       ?Total                             120    11a. State the null and…