The decomposition of hydrogen peroxide in dilute sodium hydroxide at room temperature is as follows: 2 H2O2(aq) → 2 H2O(l) + O2(g) The reaction is first-order in H2O2. The rate constant for the decomposition of H2O2 at 20°C is 1.8x10-5 s1, and the initial concentration of H2O2 is 0.80 mol L-1. (i). What is the concentration of H2O2 after 8.0 hours? (ii) (iii) How long will it take for the concentration of H2O2 to drop to 0.10M? How long will it take for 75% of the H2O2 to decompose?

Question
The decomposition of hydrogen peroxide in dilute sodium hydroxide at room
temperature is as follows:
2 H2O2(aq) → 2 H2O(l) + O2(g)
The reaction is first-order in H2O2. The rate constant for the decomposition of
H2O2 at 20°C is 1.8x10-5 s1, and the initial concentration of H2O2 is 0.80 mol L-1.
(i). What is the concentration of H2O2 after 8.0 hours?
(ii)
(iii)
How long will it take for the concentration of H2O2 to drop to 0.10M?
How long will it take for 75% of the H2O2 to decompose?
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Transcribed Image Text

The decomposition of hydrogen peroxide in dilute sodium hydroxide at room temperature is as follows: 2 H2O2(aq) → 2 H2O(l) + O2(g) The reaction is first-order in H2O2. The rate constant for the decomposition of H2O2 at 20°C is 1.8x10-5 s1, and the initial concentration of H2O2 is 0.80 mol L-1. (i). What is the concentration of H2O2 after 8.0 hours? (ii) (iii) How long will it take for the concentration of H2O2 to drop to 0.10M? How long will it take for 75% of the H2O2 to decompose?

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