The diagram shows a thin rod of uniform mass distribution pivoted about one end by a pin passing through that point. The mass of the rod is 0.480 kg and its length is 1.20 m. When the rod is released from its horizontal position, it swings down to the vertical position as shown. L/2 L. CG (a) (a) Determine the speed of its center of gravity at its lowest position in m/s. m/s (b) When the rod reaches the vertical position, calculate the tangential speed of the free end of the rod in m/s. m/s

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The diagram shows a thin rod of uniform mass distribution pivoted about one end by a pin passing through that point. The mass of the rod is 0.480 kg and its length is 1.20 m. When the
rod is released from its horizontal position, it swings down to the vertical position as shown.
M
L/2
L• CG
(a) (a) Determine the speed of its center of gravity at its lowest position in m/s.
m/s
(b) When the rod reaches the vertical position, calculate the tangential speed of the free end of the rod in m/s.
m/s
Transcribed Image Text:The diagram shows a thin rod of uniform mass distribution pivoted about one end by a pin passing through that point. The mass of the rod is 0.480 kg and its length is 1.20 m. When the rod is released from its horizontal position, it swings down to the vertical position as shown. M L/2 L• CG (a) (a) Determine the speed of its center of gravity at its lowest position in m/s. m/s (b) When the rod reaches the vertical position, calculate the tangential speed of the free end of the rod in m/s. m/s
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