Question

The distance (in feet) of an object from a point is given by s(t)=−5t^2+1, where t is in seconds. Round your answer to two decimal places.

What is the average velocity of the object between t=1.5 and t=6?

By using smaller and smaller intervals around 1.5, estimate the instantaneous velocity at time t=1.5.

Step 1

We need to find the average rate (speed) between the given time and the exact rate of change at the given instant.

Step 2

Let P denote the fixed point and Q and R be the positions at instants t=1.5 and t=6 respectively.

Step 3

the distances travelled at the two instants a...

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