The distance (in feet) of an object from a point is given by s(t)=−5t^2+1, where t is in seconds. Round your answer to two decimal places.What is the average velocity of the object between t=1.5 and t=6?By using smaller and smaller intervals around 1.5, estimate the instantaneous velocity at time t=1.5.

Question

The distance (in feet) of an object from a point is given by s(t)=−5t^2+1, where t is in seconds. Round your answer to two decimal places.
What is the average velocity of the object between t=1.5 and t=6?
By using smaller and smaller intervals around 1.5, estimate the instantaneous velocity at time t=1.5.