Question
Asked Nov 2, 2019
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The electron beam in a TV picture tube Carrie's 1015 electrons per second. Determine the voltage needed to accelerate the electron beam to achieve a power of 4 W.

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Expert Answer

Step 1

In the given problem the electron beams are generated from the cathode and accelerated towards the screen. The current carried by the given electron beam is calculated as shown below:

the rate of electron in the picture tube per second is given as
1015
t
the charge carried by this number of electron in the picture tube per second is given as
1015 x1.6x1019 4{charge on the electron is1.6 x1019 C
. the current flowing in the beam is I as
OP
dT
I = 1015 x1.6x10-19 A
I = 1.6x10 A
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the rate of electron in the picture tube per second is given as 1015 t the charge carried by this number of electron in the picture tube per second is given as 1015 x1.6x1019 4{charge on the electron is1.6 x1019 C . the current flowing in the beam is I as OP dT I = 1015 x1.6x10-19 A I = 1.6x10 A

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Step 2

The power of the given electron beam is 4W and the current flowing in the beam is calculated above. The electron beam in the  TV picture tube is shown below:

positive plate
cathode plate
P 4W
i-0.00016A
screen
negative plate
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positive plate cathode plate P 4W i-0.00016A screen negative plate

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Step 3

The power of the given  beam of electron carryin...

P V xI
where I is the current flowing in the circuit
V is the voltage across the circuit
P
V
I
-Volts
V
1.6x10 A
V 2.5x10 Volts
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P V xI where I is the current flowing in the circuit V is the voltage across the circuit P V I -Volts V 1.6x10 A V 2.5x10 Volts

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