The equilibrium constant in terms of pressures for the reduction of tungsten (VI) oxide to tungsten at 25 °C is Kp = 21.1, corresponding to the reaction WO3(s) + 3CO(g) W(s) + 3C0₂(9) If the total pressure of an equilibrium system at 25 °C is 2.96 atm, calculate the partial pressures of CO(g) and CO2(9). Pco = PCO₂ atm atm

Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
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Chapter14: Chemical Equilibrium
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The equilibrium constant in terms of pressures for the reduction of tungsten (VI) oxide to tungsten at 25 °C is Kp = 21.1, corresponding to the reaction
WO3(s) + 3CO(g)
W(s) + 3C0₂(9)
If the total pressure of an equilibrium system at 25 °C is 2.96 atm, calculate the partial pressures of CO(g) and CO₂(9).
Pco =
PCO₂
atm
atm
Transcribed Image Text:The equilibrium constant in terms of pressures for the reduction of tungsten (VI) oxide to tungsten at 25 °C is Kp = 21.1, corresponding to the reaction WO3(s) + 3CO(g) W(s) + 3C0₂(9) If the total pressure of an equilibrium system at 25 °C is 2.96 atm, calculate the partial pressures of CO(g) and CO₂(9). Pco = PCO₂ atm atm
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