Question
Asked Sep 24, 2019
The equilibrium constant, Kp, for the following reaction is 0.215 at 673 K.

NH4I(s) NH3(g) + HI(g)


If ΔH° for this reaction is 182 kJ, what is the value of Kp at 764 K?

Kp = ______

 
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Step 1

The expression for van’t Hoff equation is expressed in equation (1) in which KP1 and KP2 are equilibrium constants, T1 and T2 are two different temperatures, ∆H is the enthalpy for the reaction and R is the gas constant.

The relation between joule and kilojoule is labelled in equation (2).

К,
In
K
К,
P
ΔΗ
vap
1 1
(1)
Т, т,
R
T, T,
2
1 kJ 1000 J..... (2)
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К, In K К, P ΔΗ vap 1 1 (1) Т, т, R T, T, 2 1 kJ 1000 J..... (2)

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Step 2

Convert 182 kJ into joules by using the equation (2).

182 kJ = 182 ×1000J

           = 182000 J

Step 3

Use the equation (2) and substitute 0.215 for KP1, 673 K for T1, 764 K for T2 , 8.314 J/K.mol for R and 182000 J/mol for ∆H○ as shown below i...

K.
р2
In
182000J/mol
1
1
8.314 J/K.mol
0.215
673 K 764 K
К,
In
21890.79 K (0.0015-0.0013 K)
0.215
р2
(3)
К.
р2
-4.378
In
0.215
К,
р2
4.378
0.215
К.
P2
.... (4)
79.68
0.215
K 17.13
р2
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K. р2 In 182000J/mol 1 1 8.314 J/K.mol 0.215 673 K 764 K К, In 21890.79 K (0.0015-0.0013 K) 0.215 р2 (3) К. р2 -4.378 In 0.215 К, р2 4.378 0.215 К. P2 .... (4) 79.68 0.215 K 17.13 р2

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