The equivalent conductance of a 0.0140N solution of chloroacetic acid is 109.0 at 250C. What is the ionization constant (Ka) of chloroacetic acid
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- The equivalent conductance of a 0.0140N solution of chloroacetic acid is 109.0 at 25 degrees C. What is the ionization constant (Ka) of chloroacetic acid?If the specific conductance of a 0.02N acetic acid is 105.3 at 25oC, what is the ionization constant if the molar conductivity is 325.0?The molar conductivity of a 0.05 M solution of a weak base (B) is 4.9 x 10-1 mSm2/mol and the sum of the limiting ionic conductivities for BH+ and OH‑ is 23.7 mSm2/mol. What is the value of the base constant Kb?
- 1The equivalent conductance of a 0.0140N solution of chloroacetic acid is 109.0 at 250C. What is the ionization constant (Ka) of chloroacetic acid? Please answer very soon will give rating surelyThe molar conductivity of 0.0250 M HCOOH (aq) is 4.61 mSm^2/mol. Determine the pKa of the acid.If the cell constants of 0.2 cm^-1 and the molar conductivity of H+ and Cl- are known, 350 S.cm^2.mol^-1 and 76 S.cm^2.mol^-1, respectively, calculate the electrical conductivity of a 0.01 M HCl solution !
- The molar conductivity of 0.010 M CH3COOH(aq) is 1.65 mS m2 mol-1. What is the acidity constant, Ka, of the acid?Calculate the degree of dissociation (a) of acetic acid if its molar conductivity (Λm) is 39.05 S cm2 mol-1.Given: λ°(H+) = 349.6 S cm2 mol-1 and λ°(CH3COO–) = 40.9 S cm2 mol-11)The equivalent conductivity of 0.0108 molar aniline hydrochloride is 118,6 ohm-1 cm-1 . When the solution saturated with aniline the equivalent conductivity decreased to 103.6 ohm-1 cm-1 . The same concentration these equivalent conductivity of HCl is 411.7 ohm-1 cm2 . Calculate the hydrolysis degree of aniline hydrochloride. Explain the variation of the cell constant (K) with the amount of sample volume. 2) A strong electrolyte has an equivalent conductivity of 140 Ώ.cm . eq mol for a concentration of 2 x 10-4 eq.mol / L. The saturated solution corresponds to a concentration of 3.3 x 10-4 eq.mol / L and at an equivalent conductivity of 144.74 Ώ.cm . eq mol-1 . Determine the limit conductivity of this electrolyte. 3) Calculate the activity coefficient of the chloride ion in MgCl2 10-3 mol / L and in LaCl3 of the same concentration. What can you conclude from this?
- The conductivity of 0.001 M acetic acid is 4 × 10-5 S/cm. Calculate the dissociation constant of acetic acid, if molar conductivity at infinite dilution for acetic acid is 390 S cm2/mol.The limiting molar conductivities of KCl, KNO3 and AgNO3 are 14.99, 14.50 and 13.34 mS-m2/mol, respectively (all at 25 °C). What is the limiting molar conductivity of AgCl at this temperature?A conductivity cell has a resistance of 250 Ω when filled with 0.02 M KCl at 25°C and 105 Ω when filled with 6 x 10-5 M ammonium hydroxide solution. The conductivity of 0.02 M KCl solution at 25°C is 0.277 Sm-1, and the limiting molar ionic conductivities of NH4 + and OH- are 7.34 x 10-3 and 0.0198 S m2mol-1 , respectively. Calculate the cell constant and degree of dissociation of ammonium hydroxide in the 6 x 10-5 M solution.
