Question
Asked Nov 25, 2019
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  • the feed to distillation column is 100gmole/h. the feed composition is 40 mol℅ benzene and the rest is toluene. there are two products P1 and P2. the ratio of the two products is 1/2 and P1 is 90 mol℅ benzene. Calculate the flow rate and composition of P2
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Expert Answer

Step 1

Let, Benzene = B and Toluene = T

 

xF = 0.4 mol B/mol (mole fraction of benzene in feed stream)

yB = 0.9 mol B/mol (mole fraction of benzene in product 1 stream)

 

Basis of the calculation is taken as 100 mol/h of feed. Schematic diagram of the given process is:

Product 1, P molh
90 mol% B
10 mol% T
Feed, F 100 mol/h
Distillation
Column
40 mol% B
60 mol% T
Product 2, P mol/h
x mol% B
xmol% T
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Product 1, P molh 90 mol% B 10 mol% T Feed, F 100 mol/h Distillation Column 40 mol% B 60 mol% T Product 2, P mol/h x mol% B xmol% T

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Step 2

The ratio of the two products is given as:

Р. 2
2P P
. (1)
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Р. 2 2P P . (1)

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Step 3

Apply mole balance for the ...

F P+P
Substitute the value of P from equation (1) and
calculate the value of P as
100 P2P
3P 100
P 33.33 mol/h
=
Now
P 2P
P 2x 33.33
P 66.67 mol/h
help_outline

Image Transcriptionclose

F P+P Substitute the value of P from equation (1) and calculate the value of P as 100 P2P 3P 100 P 33.33 mol/h = Now P 2P P 2x 33.33 P 66.67 mol/h

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